Aeromexico AM5397 Flight Status Today

Domestic flight Aeromexico AM5397 takes off from Dulles (IAD) United States to New York (JFK) United States. It's operated by Aeromexico. The plane leaves Washington Dulles International Airport at 06:00 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 07:29 America/New_York. The flight will last about 1 hours 18 minutes.

AM5397 - AMX5397 Aeromexico (AM)
IAD Dulles United States
Flight IAD to JFK
JFK New York United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 05-January-2020
Departure Washington Dulles International Airport
IATA: IADICAO: KIAD
Scheduled 06:00
None B70
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 07:29
4 B55
AM5397 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 18 minutes
  • Flight Distance: 365 kms / 227 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 50
  • Freight capacity: 1.5 tons
  • Passenger classes: Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: CRJ2
  • Callsign: AMX5397
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Dulles: Wednesday 2026-03-25 00:38 AM
  • Current Time in New York: Wednesday 2026-03-25 00:38 AM

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Aeromexico Flight AM5397 FAQs

What is the scheduled flight duration for Aeromexico AM5397 flight?

On average, nonstop flight takes 1 hour(s) 18 minutes, with the flight distance of 365 km (227 miles).

What type of aircraft is used for the Aeromexico AM5397 flight?

All Aeromexico AM5397 flights are operated using CRJ2 aircraft.

Which terminal the flight Aeromexico AM5397 is arriving at?

Flight Aeromexico AM5397 arrives in John F. Kennedy International Airport at Terminal 4.