Aeromexico AM5372 Flight Status Today

Domestic flight Aeromexico AM5372 takes off from Cleveland (CLE) United States to Atlanta (ATL) United States. It's operated by Aeromexico. The plane leaves Cleveland Hopkins International Airport at 07:00 America/New_York. The flight is expected to land at Hartsfield-Jackson Atlanta International Airport at 08:48 America/New_York. The flight will last about 1 hours 30 minutes.

AM5372 - AMX5372 Aeromexico (AM)
CLE Cleveland United States
Flight CLE to ATL
ATL Atlanta United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 03-January-2021
Departure Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 07:00
None B2
Arrival Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 08:48
S B20
AM5372 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 30 minutes
  • Flight Distance: 893 kms / 555 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 158
  • Freight capacity: 3.1 tons
  • Passenger classes: Economy, Business Class, Shuttle, Premium Economy
More Detail
  • Aircraft: MD90
  • Callsign: AMX5372
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Cleveland: Friday 2026-04-10 09:48 AM
  • Current Time in Atlanta: Friday 2026-04-10 09:48 AM

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Aeromexico Flight AM5372 FAQs

What is the scheduled flight duration for Aeromexico AM5372 flight?

On average, nonstop flight takes 1 hour(s) 30 minutes, with the flight distance of 893 km (555 miles).

What type of aircraft is used for the Aeromexico AM5372 flight?

All Aeromexico AM5372 flights are operated using MD90 aircraft.

Which terminal the flight Aeromexico AM5372 is arriving at?

Flight Aeromexico AM5372 arrives in Hartsfield-Jackson Atlanta International Airport at Terminal S.