Aeromexico AM5343 Flight Status Today

Domestic flight Aeromexico AM5343 takes off from Atlanta (ATL) United States to Milwaukee (MKE) United States. It's operated by Aeromexico. The plane leaves Hartsfield-Jackson Atlanta International Airport at 17:51 America/New_York. The flight is expected to land at General Mitchell International Airport at 18:58 America/Chicago. The flight will last about 2 hours 7 minutes.

AM5343 - AMX5343 Aeromexico (AM)
ATL Atlanta United States
Flight ATL to MKE
MKE Milwaukee United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 11-March-2020
Departure Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 17:51
S D24
Arrival General Mitchell International Airport
IATA: MKEICAO: KMKE
Scheduled 18:58
None D44
AM5343 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 7 minutes
  • Flight Distance: 1076 kms / 669 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 110
  • Freight capacity: 1 tons
  • Passenger classes: Economy, Business Class, Shuttle, Premium Economy
More Detail
  • Aircraft: Airbus A319
  • Callsign: AMX5343
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Chicago
  • Current Time in Atlanta: Friday 2026-03-20 13:46 PM
  • Current Time in Milwaukee: Friday 2026-03-20 12:46 PM

Flight routes similar to Aeromexico AM5343

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Air France AF5736
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Aeromexico Flight AM5343 FAQs

What is the scheduled flight duration for Aeromexico AM5343 flight?

On average, nonstop flight takes 2 hour(s) 7 minutes, with the flight distance of 1076 km (669 miles).

What type of aircraft is used for the Aeromexico AM5343 flight?

All Aeromexico AM5343 flights are operated using Airbus A319 aircraft.