Aeromexico AM5308 Flight Status Today

Domestic flight Aeromexico AM5308 takes off from New York (JFK) United States to Los Angeles (LAX) United States. It's operated by Aeromexico. The plane leaves John F. Kennedy International Airport at 08:00 America/New_York. The flight is expected to land at Los Angeles International Airport at 11:19 America/Los_Angeles. The flight will last about 6 hours 19 minutes.

AM5308 - AMX5308 Aeromexico (AM)
JFK New York United States
Flight JFK to LAX
LAX Los Angeles United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 22-February-2019
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 08:00
4 27
Arrival Los Angeles International Airport
IATA: LAXICAO: KLAX
Scheduled 11:19
2 None
AM5308 Detail
  • Type: Domestic Flight
  • Flight Duration: 6 hours 19 minutes
  • Flight Distance: 3982 kms / 2474 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 293
  • Freight capacity: 10 tons
  • Passenger classes: Economy, Business Class, Shuttle, Premium Economy
More Detail
  • Aircraft: Airbus A330-300
  • Callsign: AMX5308
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Los_Angeles
  • Current Time in New York: Sunday 2025-12-28 20:41 PM
  • Current Time in Los Angeles: Sunday 2025-12-28 17:41 PM

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Aeromexico Flight AM5308 FAQs

What is the scheduled flight duration for Aeromexico AM5308 flight?

On average, nonstop flight takes 6 hour(s) 19 minutes, with the flight distance of 3982 km (2474 miles).

What type of aircraft is used for the Aeromexico AM5308 flight?

All Aeromexico AM5308 flights are operated using Airbus A330-300 aircraft.

Which terminal the flight Aeromexico AM5308 is arriving at?

Flight Aeromexico AM5308 arrives in Los Angeles International Airport at Terminal 2.