Aeromexico AM5270 Flight Status Today

Domestic flight Aeromexico AM5270 takes off from New York (JFK) United States to Atlanta (ATL) United States. It's operated by Aeromexico. The plane leaves John F. Kennedy International Airport at 14:00 America/New_York. The flight is expected to land at Hartsfield-Jackson Atlanta International Airport at 16:27 America/New_York. The flight will last about 1 hours 58 minutes.

AM5270 - AMX5270 Aeromexico (AM)
JFK New York United States
Flight JFK to ATL
ATL Atlanta United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 01-April-2020
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 14:00
Arrival Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 16:27
S
AM5270 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 58 minutes
  • Flight Distance: 1223 kms / 760 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 180
  • Freight capacity: 17.1 tons
  • Passenger classes: Economy, Business Class, Shuttle, Premium Economy
More Detail
  • Aircraft: Boeing 737-900 Passenger
  • Callsign: AMX5270
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Sunday 2025-12-28 20:50 PM
  • Current Time in Atlanta: Sunday 2025-12-28 20:50 PM

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Aeromexico Flight AM5270 FAQs

What is the scheduled flight duration for Aeromexico AM5270 flight?

On average, nonstop flight takes 1 hour(s) 58 minutes, with the flight distance of 1223 km (760 miles).

What type of aircraft is used for the Aeromexico AM5270 flight?

All Aeromexico AM5270 flights are operated using Boeing 737-900 Passenger aircraft.

Which terminal the flight Aeromexico AM5270 is arriving at?

Flight Aeromexico AM5270 arrives in Hartsfield-Jackson Atlanta International Airport at Terminal S.