Aeromexico AM5148 Flight Status Today

Domestic flight Aeromexico AM5148 takes off from New York (JFK) United States to Rochester (ROC) United States. It's operated by Aeromexico. The plane leaves John F. Kennedy International Airport at 15:19 America/New_York. The flight is expected to land at Greater Rochester International Airport at 16:48 America/New_York. The flight will last about 1 hours 33 minutes.

AM5148 - AMX5148 Aeromexico (AM)
JFK New York United States
Flight JFK to ROC
ROC Rochester United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 10-April-2020
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 15:19
4 B55
Arrival Greater Rochester International Airport
IATA: ROCICAO: KROC
Scheduled 16:48
None B1
AM5148 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 33 minutes
  • Flight Distance: 424 kms / 263 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 1.9 tons
  • Passenger classes: Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: CRJ9
  • Callsign: AMX5148
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Monday 2026-03-02 16:26 PM
  • Current Time in Rochester: Monday 2026-03-02 16:26 PM

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Aeromexico Flight AM5148 FAQs

What is the scheduled flight duration for Aeromexico AM5148 flight?

On average, nonstop flight takes 1 hour(s) 33 minutes, with the flight distance of 424 km (263 miles).

What type of aircraft is used for the Aeromexico AM5148 flight?

All Aeromexico AM5148 flights are operated using CRJ9 aircraft.