Aeromexico AM5107 Flight Status Today

Domestic flight Aeromexico AM5107 takes off from Atlanta (ATL) United States to Knoxville (TYS) United States. It's operated by Aeromexico. The plane leaves Hartsfield-Jackson Atlanta International Airport at 22:36 America/New_York. The flight is expected to land at McGhee Tyson Airport at 23:30 America/New_York. The flight will last about 29 minutes.

AM5107 - AMX5107 Aeromexico (AM)
ATL Atlanta United States
Flight ATL to TYS
TYS Knoxville United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 04-April-2020
Departure Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 22:36
S
Arrival McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled 23:30
MAIN
AM5107 Detail
  • Type: Domestic Flight
  • Flight Duration: 29 minutes
  • Flight Distance: 244 kms / 152 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 149
  • Freight capacity: 5.7 tons
  • Passenger classes: Economy, Business Class, Shuttle, Premium Economy
More Detail
  • Aircraft: MD88
  • Callsign: AMX5107
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Atlanta: Friday 2026-04-10 01:43 AM
  • Current Time in Knoxville: Friday 2026-04-10 01:43 AM

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Aeromexico Flight AM5107 FAQs

What is the scheduled flight duration for Aeromexico AM5107 flight?

On average, nonstop flight takes 29 minutes, with the flight distance of 244 km (152 miles).

What type of aircraft is used for the Aeromexico AM5107 flight?

All Aeromexico AM5107 flights are operated using MD88 aircraft.

Which terminal the flight Aeromexico AM5107 is arriving at?

Flight Aeromexico AM5107 arrives in McGhee Tyson Airport at Terminal MAIN.