Aeromexico AM5045 Flight Status Today

Domestic flight Aeromexico AM5045 takes off from Chattanooga (CHA) United States to Atlanta (ATL) United States. It's operated by Aeromexico. The plane leaves Chattanooga Airport at 10:40 America/New_York. The flight is expected to land at Hartsfield-Jackson Atlanta International Airport at 11:37 America/New_York. The flight will last about 37 minutes.

AM5045 - AMX5045 Aeromexico (AM)
CHA Chattanooga United States
Flight CHA to ATL
ATL Atlanta United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 01-April-2020
Departure Chattanooga Airport
IATA: CHAICAO: KCHA
Scheduled 10:40
MAIN
Arrival Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 11:37
S
AM5045 Detail
  • Type: Domestic Flight
  • Flight Duration: 37 minutes
  • Flight Distance: 170 kms / 105 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 50
  • Freight capacity: 1.5 tons
  • Passenger classes: Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: CRJ
  • Callsign: AMX5045
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Chattanooga: Thursday 2026-04-09 17:57 PM
  • Current Time in Atlanta: Thursday 2026-04-09 17:57 PM

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Aeromexico Flight AM5045 FAQs

What is the scheduled flight duration for Aeromexico AM5045 flight?

On average, nonstop flight takes 37 minutes, with the flight distance of 170 km (105 miles).

What type of aircraft is used for the Aeromexico AM5045 flight?

All Aeromexico AM5045 flights are operated using CRJ aircraft.

Which terminal the flight Aeromexico AM5045 is arriving at?

Flight Aeromexico AM5045 arrives in Hartsfield-Jackson Atlanta International Airport at Terminal S.