Aeromexico AM4974 Flight Status Today

Domestic flight Aeromexico AM4974 takes off from Greenville (GSP) United States to Atlanta (ATL) United States. It's operated by Aeromexico. The plane leaves Greenville-Spartanburg International Airport at 05:30 America/New_York. The flight is expected to land at Hartsfield-Jackson Atlanta International Airport at 06:29 America/New_York. The flight will last about 0 minutes.

AM4974 - AMX4974 Aeromexico (AM)
GSP Greenville United States
Flight GSP to ATL
ATL Atlanta United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Greenville-Spartanburg International Airport
IATA: GSPICAO: KGSP
Scheduled 05:30
None B4
Arrival Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 06:29
S E10
AM4974 Detail
  • Type: Domestic Flight
  • Flight Duration: 0 minutes
  • Flight Distance: 248 kms / 154 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 192
  • Freight capacity: 4.6 tons
  • Passenger classes: Economy, Business Class, Shuttle, Premium Economy
More Detail
  • Aircraft: Boeing 737-900 (winglets) Passenger/BBJ3
  • Callsign: AMX4974
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Greenville: Friday 2026-05-01 21:07 PM
  • Current Time in Atlanta: Friday 2026-05-01 21:07 PM

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Aeromexico Flight AM4974 FAQs

What is the scheduled flight duration for Aeromexico AM4974 flight?

On average, nonstop flight takes 0 minutes, with the flight distance of 248 km (154 miles).

What type of aircraft is used for the Aeromexico AM4974 flight?

All Aeromexico AM4974 flights are operated using Boeing 737-900 (winglets) Passenger/BBJ3 aircraft.

Which terminal the flight Aeromexico AM4974 is arriving at?

Flight Aeromexico AM4974 arrives in Hartsfield-Jackson Atlanta International Airport at Terminal S.