Aeromexico AM4947 Flight Status Today

Domestic flight Aeromexico AM4947 takes off from Detroit (DTW) United States to Houston (IAH) United States. It's operated by Aeromexico. The plane leaves Detroit Metropolitan Wayne County Airport at 17:50 America/New_York. The flight is expected to land at George Bush Intercontinental Airport at 19:57 America/Chicago. The flight will last about 3 hours 30 minutes.

AM4947 - AMX4947 Aeromexico (AM)
DTW Detroit United States
Flight DTW to IAH
IAH Houston United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 12-April-2020
Departure Detroit Metropolitan Wayne County Airport
IATA: DTWICAO: KDTW
Scheduled 17:50
M B18
Arrival George Bush Intercontinental Airport
IATA: IAHICAO: KIAH
Scheduled 19:57
A 10
AM4947 Detail
  • Type: Domestic Flight
  • Flight Duration: 3 hours 30 minutes
  • Flight Distance: 1730 kms / 1075 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 1.9 tons
  • Passenger classes: Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: Canadair CRJ 900
  • Callsign: AMX4947
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Chicago
  • Current Time in Detroit: Tuesday 2026-03-03 06:35 AM
  • Current Time in Houston: Tuesday 2026-03-03 05:35 AM

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WestJet WS6891
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United Airlines UA6251
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Delta DL1718
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KLM KL5540
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Aeromexico Flight AM4947 FAQs

What is the scheduled flight duration for Aeromexico AM4947 flight?

On average, nonstop flight takes 3 hour(s) 30 minutes, with the flight distance of 1730 km (1075 miles).

What type of aircraft is used for the Aeromexico AM4947 flight?

All Aeromexico AM4947 flights are operated using Canadair CRJ 900 aircraft.

Which terminal the flight Aeromexico AM4947 is arriving at?

Flight Aeromexico AM4947 arrives in George Bush Intercontinental Airport at Terminal A.