Aeromexico AM4934 Flight Status Today

Domestic flight Aeromexico AM4934 takes off from New York (JFK) United States to Cleveland (CLE) United States. It's operated by Aeromexico. The plane leaves John F. Kennedy International Airport at 19:25 America/New_York. The flight is expected to land at Cleveland Hopkins International Airport at 21:38 America/New_York. The flight will last about 2 hours 13 minutes.

AM4934 - AMX4934 Aeromexico (AM)
JFK New York United States
Flight JFK to CLE
CLE Cleveland United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 31-August-2019
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 19:25
4 B48
Arrival Cleveland Hopkins International Airport
IATA: CLEICAO: KCLE
Scheduled 21:38
None B5
AM4934 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 13 minutes
  • Flight Distance: 682 kms / 424 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 1.9 tons
  • Passenger classes: Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: CRJ9
  • Callsign: AMX4934
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Friday 2026-02-06 23:51 PM
  • Current Time in Cleveland: Friday 2026-02-06 23:51 PM

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Virgin Atlantic VS3149
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El Al LY4246
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Aeromexico Flight AM4934 FAQs

What is the scheduled flight duration for Aeromexico AM4934 flight?

On average, nonstop flight takes 2 hour(s) 13 minutes, with the flight distance of 682 km (424 miles).

What type of aircraft is used for the Aeromexico AM4934 flight?

All Aeromexico AM4934 flights are operated using CRJ9 aircraft.