Aeromexico AM4893 Flight Status Today

Domestic flight Aeromexico AM4893 takes off from Atlanta (ATL) United States to Asheville (AVL) United States. It's operated by Aeromexico. The plane leaves Hartsfield-Jackson Atlanta International Airport at 15:25 America/New_York. The flight is expected to land at Asheville Regional Airport at 16:26 America/New_York. The flight will last about 1 hours 5 minutes.

AM4893 - AMX4893 Aeromexico (AM)
ATL Atlanta United States
Flight ATL to AVL
AVL Asheville United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 01-January-2020
Departure Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 15:25
S F9
Arrival Asheville Regional Airport
IATA: AVLICAO: KAVL
Scheduled 16:26
None B3
AM4893 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 5 minutes
  • Flight Distance: 265 kms / 165 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 1.9 tons
  • Passenger classes: Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: CRJ9
  • Callsign: AMX4893
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Atlanta: Friday 2026-02-27 09:12 AM
  • Current Time in Asheville: Friday 2026-02-27 09:12 AM

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Aeromexico Flight AM4893 FAQs

What is the scheduled flight duration for Aeromexico AM4893 flight?

On average, nonstop flight takes 1 hour(s) 5 minutes, with the flight distance of 265 km (165 miles).

What type of aircraft is used for the Aeromexico AM4893 flight?

All Aeromexico AM4893 flights are operated using CRJ9 aircraft.