Aeromexico AM4885 Flight Status Today

Domestic flight Aeromexico AM4885 takes off from New Orleans (MSY) United States to Atlanta (ATL) United States. It's operated by Aeromexico. The plane leaves Louis Armstrong New Orleans International Airport at 12:16 America/Chicago. The flight is expected to land at Hartsfield-Jackson Atlanta International Airport at 14:55 America/New_York. The flight will last about 1 hours 28 minutes.

AM4885 - AMX4885 Aeromexico (AM)
MSY New Orleans United States
Flight MSY to ATL
ATL Atlanta United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 04-August-2021
Departure Louis Armstrong New Orleans International Airport
IATA: MSYICAO: KMSY
Scheduled 12:16
None C4
Arrival Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 14:55
S A30
AM4885 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 28 minutes
  • Flight Distance: 683 kms / 425 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 180
  • Freight capacity: 17.1 tons
  • Passenger classes: Economy, Business Class, Shuttle, Premium Economy
More Detail
  • Aircraft: Boeing 737-900 (winglets) Passenger/BBJ3
  • Callsign: AMX4885
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/New_York
  • Current Time in New Orleans: Saturday 2026-05-02 17:28 PM
  • Current Time in Atlanta: Saturday 2026-05-02 18:28 PM

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Aeromexico Flight AM4885 FAQs

What is the scheduled flight duration for Aeromexico AM4885 flight?

On average, nonstop flight takes 1 hour(s) 28 minutes, with the flight distance of 683 km (425 miles).

What type of aircraft is used for the Aeromexico AM4885 flight?

All Aeromexico AM4885 flights are operated using Boeing 737-900 (winglets) Passenger/BBJ3 aircraft.

Which terminal the flight Aeromexico AM4885 is arriving at?

Flight Aeromexico AM4885 arrives in Hartsfield-Jackson Atlanta International Airport at Terminal S.