Aeromexico AM4877 Flight Status Today

Domestic flight Aeromexico AM4877 takes off from Chattanooga (CHA) United States to Atlanta (ATL) United States. It's operated by Aeromexico. The plane leaves Chattanooga Airport at 08:25 America/New_York. The flight is expected to land at Hartsfield-Jackson Atlanta International Airport at 09:20 America/New_York. The flight will last about 55 minutes.

AM4877 - AMX4877 Aeromexico (AM)
CHA Chattanooga United States
Flight CHA to ATL
ATL Atlanta United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 07-June-2019
Departure Chattanooga Airport
IATA: CHAICAO: KCHA
Scheduled 08:25
3
Arrival Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 09:20
S D09
AM4877 Detail
  • Type: Domestic Flight
  • Flight Duration: 55 minutes
  • Flight Distance: 170 kms / 105 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 1.9 tons
  • Passenger classes: Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: CRJ9
  • Callsign: AMX4877
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Chattanooga: Thursday 2026-02-26 21:29 PM
  • Current Time in Atlanta: Thursday 2026-02-26 21:29 PM

Flight routes similar to Aeromexico AM4877

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Delta DL2103
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KLM KL5217
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Delta DL2110
Delta 		26/02/2026
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WestJet WS6720
WestJet 		26/02/2026
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Aeromexico Flight AM4877 FAQs

What is the scheduled flight duration for Aeromexico AM4877 flight?

On average, nonstop flight takes 55 minutes, with the flight distance of 170 km (105 miles).

What type of aircraft is used for the Aeromexico AM4877 flight?

All Aeromexico AM4877 flights are operated using CRJ9 aircraft.

Which terminal the flight Aeromexico AM4877 is arriving at?

Flight Aeromexico AM4877 arrives in Hartsfield-Jackson Atlanta International Airport at Terminal S.