Aeromexico AM4800 Flight Status Today

Domestic flight Aeromexico AM4800 takes off from Detroit (DTW) United States to Columbus (CMH) United States. It's operated by Aeromexico. The plane leaves Detroit Metropolitan Wayne County Airport at 19:59 America/New_York. The flight is expected to land at John Glenn Columbus International Airport at 21:09 America/New_York. The flight will last about 1 hours 10 minutes.

AM4800 - AMX4800 Aeromexico (AM)
DTW Detroit United States
Flight DTW to CMH
CMH Columbus United States
Contact Airlines It may not operate on the date requested
Departure Detroit Metropolitan Wayne County Airport
IATA: DTWICAO: KDTW
Scheduled 19:59
M B15
Arrival John Glenn Columbus International Airport
IATA: CMHICAO: KCMH
Scheduled 21:09
None C53
AM4800 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 10 minutes
  • Flight Distance: 249 kms / 154 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Saturday, Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 149
  • Freight capacity: 5.7 tons
  • Passenger classes: Economy, Business Class, Shuttle, Premium Economy
More Detail
  • Aircraft: Embraer 175
  • Callsign: AMX4800
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Detroit: Sunday 2026-02-08 23:21 PM
  • Current Time in Columbus: Sunday 2026-02-08 23:21 PM

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Aeromexico Flight AM4800 FAQs

What is the scheduled flight duration for Aeromexico AM4800 flight?

On average, nonstop flight takes 1 hour(s) 10 minutes, with the flight distance of 249 km (154 miles).

What type of aircraft is used for the Aeromexico AM4800 flight?

All Aeromexico AM4800 flights are operated using Embraer 175 aircraft.

How many Aeromexico AM4800 flights are operated a week?

6 flights per week. The Flight Aeromexico AM4800 is operated on Monday, Tuesday, Wednesday, Thursday, Saturday, Sunday.