Aeromexico AM4775 Flight Status Today

Domestic flight Aeromexico AM4775 takes off from Minneapolis (MSP) United States to Minot (MOT) United States. It's operated by Aeromexico. The plane leaves Minneapolis Airport at 21:50 America/Chicago. The flight is expected to land at Minot International Airport at 23:30 America/Chicago. The flight will last about 1 hours 40 minutes.

AM4775 - AMX4775 Aeromexico (AM)
MSP Minneapolis United States
Flight MSP to MOT
MOT Minot United States
Contact Airlines It may not operate on the date requested
Departure Minneapolis Airport
IATA: MSPICAO: KMSP
Scheduled 21:50
1 C26
Arrival Minot International Airport
IATA: MOTICAO: KMOT
Scheduled 23:30
None None
AM4775 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 40 minutes
  • Flight Distance: 724 kms / 450 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: Monday
Passenger Services
  • Service type: Normal passenger
  • Seats: 149
  • Freight capacity: 5.7 tons
  • Passenger classes: Economy, Business Class, Shuttle, Premium Economy
More Detail
  • Aircraft: Embraer 175
  • Callsign: AMX4775
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Chicago
  • Current Time in Minneapolis: Sunday 2026-01-18 19:57 PM
  • Current Time in Minot: Sunday 2026-01-18 19:57 PM

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Aeromexico Flight AM4775 FAQs

What is the scheduled flight duration for Aeromexico AM4775 flight?

On average, nonstop flight takes 1 hour(s) 40 minutes, with the flight distance of 724 km (450 miles).

What type of aircraft is used for the Aeromexico AM4775 flight?

All Aeromexico AM4775 flights are operated using Embraer 175 aircraft.

How many Aeromexico AM4775 flights are operated a week?

1 flights per week. The Flight Aeromexico AM4775 is operated on Monday.