Aeromexico AM4710 Flight Status Today

Domestic flight Aeromexico AM4710 takes off from Knoxville (TYS) United States to Atlanta (ATL) United States. It's operated by Aeromexico. The plane leaves McGhee Tyson Airport at 15:13 America/New_York. The flight is expected to land at Hartsfield-Jackson Atlanta International Airport at 16:16 America/New_York. The flight will last about 0 minutes.

AM4710 - AMX4710 Aeromexico (AM)
TYS Knoxville United States
Flight TYS to ATL
ATL Atlanta United States
Contact Airlines It may not operate on the date requested
Departure McGhee Tyson Airport
IATA: TYSICAO: KTYS
Scheduled 15:13
None 3
Arrival Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 16:16
S D7
AM4710 Detail
  • Type: Domestic Flight
  • Flight Duration: 0 minutes
  • Flight Distance: 244 kms / 152 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: Thursday
Passenger Services
  • Service type: Normal passenger
  • Seats: 70
  • Freight capacity: 0 tons
  • Passenger classes: Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: Canadair (Bombardier) Regional Jet 900 and Challenger 890
  • Callsign: AMX4710
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Knoxville: Monday 2026-04-13 04:32 AM
  • Current Time in Atlanta: Monday 2026-04-13 04:32 AM

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Aeromexico Flight AM4710 FAQs

What is the scheduled flight duration for Aeromexico AM4710 flight?

On average, nonstop flight takes 0 minutes, with the flight distance of 244 km (152 miles).

What type of aircraft is used for the Aeromexico AM4710 flight?

All Aeromexico AM4710 flights are operated using Canadair (Bombardier) Regional Jet 900 and Challenger 890 aircraft.

Which terminal the flight Aeromexico AM4710 is arriving at?

Flight Aeromexico AM4710 arrives in Hartsfield-Jackson Atlanta International Airport at Terminal S.

How many Aeromexico AM4710 flights are operated a week?

1 flights per week. The Flight Aeromexico AM4710 is operated on Thursday.