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Aeromexico AM4675 flight status now
Current status of AM4675 is Departed Delayed by 24m Estimated Arrival in 1 hour, 39 minutes
- Type: International Flight
- Code Shares: KL 7014
- Flight Duration: 2 hours 48 minutes
- Flight Distance: 1526 kms / 948 miles
- Aeromexico
- IATA: AM
- ICAO: AMX
- Operating Days: Monday
- Service type: Normal passenger
- Seats: 150
- Freight capacity: 9.4 tons
- Passenger classes: Economy, Business Class, Shuttle, Premium Economy
- Aircraft: Boeing 737-800 (winglets) Passenger/BBJ2
- Callsign: AMX4675
- Departure Timezone: America/Cancun
- Arrival Timezone: America/New_York
- Current Time in TULUM: Monday 2025-11-17 16:54 PM
- Current Time in Atlanta: Monday 2025-11-17 16:54 PM
International flight Aeromexico AM4675 takes off from TULUM (TQO) Mexico to Atlanta (ATL) United States. It's operated by Aeromexico. The plane leaves Felipe Carrillo Puerto Airport at 15:21 17 November 2025 America/Cancun. The flight is expected to land at Hartsfield-Jackson Atlanta International Airport at 18:09 17 November 2025 America/New_York. The flight will last about 2 hours 48 minutes.
Frequently asked questions, answered
How long is the flight from TULUM to Atlanta?
On average, nonstop flight takes 2 hour(s) 48 minutes, with the flight distance of 1526 km (948 miles).
What type of aircraft is used for the Aeromexico AM4675 flight?
All Aeromexico AM4675 flights are operated using Boeing 737-800 (winglets) Passenger/BBJ2 aircraft.
Which terminal the flight Aeromexico AM4675 is arriving at?
Flight Aeromexico AM4675 arrives in Hartsfield-Jackson Atlanta International Airport at Terminal S.
How many Aeromexico AM4675 flights are operated a week?
1 flights per week. The Flight Aeromexico AM4675 is operated on Monday.
