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Aeromexico AM4675 Flight Status
Current status of AM4675 is Scheduled On time Expected Depart in 9 hours, 51 minutes
- Type: International Flight
- Code Shares: KE 7619, KL 7014
- Flight Duration: 2 hours 47 minutes
- Flight Distance: 1526 kms / 948 miles
- Aeromexico
- IATA: AM
- ICAO: AMX
- Operating Days: Monday
- Service type: Normal passenger
- Seats: 150
- Freight capacity: 9.4 tons
- Passenger classes: Economy, Business Class, Shuttle, Premium Economy
- Aircraft: Boeing 737-800 (Scimitar Winglets) Passenger
- Callsign: AMX4675
- Departure Timezone: America/Cancun
- Arrival Timezone: America/New_York
- Current Time in TULUM: Monday 2025-12-08 05:33 AM
- Current Time in Atlanta: Monday 2025-12-08 05:33 AM
International flight Aeromexico AM4675 takes off from TULUM (TQO) Mexico to Atlanta (ATL) United States. It's operated by Aeromexico. The plane leaves Felipe Carrillo Puerto Airport at 15:24 08 December 2025 America/Cancun. The flight is expected to land at Hartsfield-Jackson Atlanta International Airport at 18:11 08 December 2025 America/New_York. The flight will last about 2 hours 47 minutes.
Frequently asked questions, answered
What is the scheduled flight duration for Aeromexico AM4675 flight?
On average, nonstop flight takes 2 hour(s) 47 minutes, with the flight distance of 1526 km (948 miles).
What is the current status of Aeromexico AM4675 flight?
The current status of flight Aeromexico AM4675 is Scheduled On time.
What type of aircraft is used for the Aeromexico AM4675 flight?
All Aeromexico AM4675 flights are operated using Boeing 737-800 (Scimitar Winglets) Passenger aircraft.
When does the flight Aeromexico AM4675 arrive?
Flight Aeromexico AM4675 arrives at 18:11.
Which terminal the flight Aeromexico AM4675 is arriving at?
Flight Aeromexico AM4675 arrives in Hartsfield-Jackson Atlanta International Airport at Terminal S.
How many Aeromexico AM4675 flights are operated a week?
1 flights per week. The Flight Aeromexico AM4675 is operated on Monday.
