Aeromexico AM4439 Flight Status Today

Domestic flight Aeromexico AM4439 takes off from Atlanta (ATL) United States to Columbus (CMH) United States. It's operated by Aeromexico. The plane leaves Hartsfield-Jackson Atlanta International Airport at 20:28 America/New_York. The flight is expected to land at John Glenn Columbus International Airport at 22:01 America/New_York. The flight will last about 1 hours 33 minutes.

AM4439 - AMX4439 Aeromexico (AM)
ATL Atlanta United States
Flight ATL to CMH
CMH Columbus United States
Contact Airlines It may not operate on the date requested
Departure Hartsfield-Jackson Atlanta International Airport
IATA: ATLICAO: KATL
Scheduled 20:28
S E37
Arrival John Glenn Columbus International Airport
IATA: CMHICAO: KCMH
Scheduled 22:01
None C54
AM4439 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 33 minutes
  • Flight Distance: 719 kms / 447 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: Monday, Wednesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 199
  • Freight capacity: 8.7 tons
  • Passenger classes: Economy, Business Class, Shuttle, Premium Economy
More Detail
  • Aircraft: Boeing 737-900 Passenger (Scimitar Winglets)
  • Callsign: AMX4439
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Atlanta: Monday 2025-12-29 01:01 AM
  • Current Time in Columbus: Monday 2025-12-29 01:01 AM

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Aeromexico Flight AM4439 FAQs

What is the scheduled flight duration for Aeromexico AM4439 flight?

On average, nonstop flight takes 1 hour(s) 33 minutes, with the flight distance of 719 km (447 miles).

What type of aircraft is used for the Aeromexico AM4439 flight?

All Aeromexico AM4439 flights are operated using Boeing 737-900 Passenger (Scimitar Winglets) aircraft.

How many Aeromexico AM4439 flights are operated a week?

6 flights per week. The Flight Aeromexico AM4439 is operated on Monday, Wednesday, Thursday, Friday, Saturday, Sunday.