Aeromexico AM4408 Flight Status Today

International flight Aeromexico AM4408 takes off from Toronto (YYZ) Canada to New York (JFK) United States. It's operated by Aeromexico. The plane leaves Pearson International Airport at 12:15 America/Toronto. The flight is expected to land at John F. Kennedy International Airport at 13:59 America/New_York. The flight will last about 1 hours 44 minutes.

AM4408 - AMX4408 Aeromexico (AM)
YYZ Toronto Canada
Flight YYZ to JFK
JFK New York United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 16-August-2020
Departure Pearson International Airport
IATA: YYZICAO: CYYZ
Scheduled 12:15
3 A6
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 13:59
4 A10
AM4408 Detail
  • Type: International Flight
  • Flight Duration: 1 hours 44 minutes
  • Flight Distance: 588 kms / 365 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 180
  • Freight capacity: 17.1 tons
  • Passenger classes: Economy, Business Class, Shuttle, Premium Economy
More Detail
  • Aircraft: Canadair (Bombardier) Regional Jet 900 and Challenger 890
  • Callsign: AMX4408
  • Departure Timezone: America/Toronto
  • Arrival Timezone: America/New_York
  • Current Time in Toronto: Sunday 2026-01-18 05:07 AM
  • Current Time in New York: Sunday 2026-01-18 05:07 AM

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Aeromexico Flight AM4408 FAQs

What is the scheduled flight duration for Aeromexico AM4408 flight?

On average, nonstop flight takes 1 hour(s) 44 minutes, with the flight distance of 588 km (365 miles).

What type of aircraft is used for the Aeromexico AM4408 flight?

All Aeromexico AM4408 flights are operated using Canadair (Bombardier) Regional Jet 900 and Challenger 890 aircraft.

Which terminal the flight Aeromexico AM4408 is arriving at?

Flight Aeromexico AM4408 arrives in John F. Kennedy International Airport at Terminal 4.