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Aeromexico AM4159 Flight Status Today
Domestic flight Aeromexico AM4159 takes off from Cleveland (CLE) United States to Atlanta (ATL) United States. It's operated by Aeromexico. The plane leaves Cleveland Hopkins International Airport at 07:05 America/New_York. The flight is expected to land at Hartsfield-Jackson Atlanta International Airport at 09:19 America/New_York. The flight will last about 2 hours 10 minutes.
- Type: Domestic Flight
- Flight Duration: 2 hours 10 minutes
- Flight Distance: 893 kms / 555 miles
- Aeromexico
- IATA: AM
- ICAO: AMX
- Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday
- Service type: Normal passenger
- Seats: 180
- Freight capacity: 17.1 tons
- Passenger classes: Economy, Business Class, Shuttle, Premium Economy
- Aircraft: Boeing 737-800 (Scimitar Winglets) Passenger
- Callsign: AMX4159
- Departure Timezone: America/New_York
- Arrival Timezone: America/New_York
- Current Time in Cleveland: Saturday 2026-02-28 17:42 PM
- Current Time in Atlanta: Saturday 2026-02-28 17:42 PM
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Aeromexico Flight AM4159 FAQs
What is the scheduled flight duration for Aeromexico AM4159 flight?
On average, nonstop flight takes 2 hour(s) 10 minutes, with the flight distance of 893 km (555 miles).
What type of aircraft is used for the Aeromexico AM4159 flight?
All Aeromexico AM4159 flights are operated using Boeing 737-800 (Scimitar Winglets) Passenger aircraft.
Which terminal the flight Aeromexico AM4159 is arriving at?
Flight Aeromexico AM4159 arrives in Hartsfield-Jackson Atlanta International Airport at Terminal S.
How many Aeromexico AM4159 flights are operated a week?
7 flights per week. The Flight Aeromexico AM4159 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday .
