Aeromexico AM4112 Flight Status Today

Domestic flight Aeromexico AM4112 takes off from New York (JFK) United States to Boston (BOS) United States. It's operated by Aeromexico. The plane leaves John F. Kennedy International Airport at 06:10 America/New_York. The flight is expected to land at Logan International Airport at 07:37 America/New_York. The flight will last about 1 hours 5 minutes.

AM4112 - AMX4112 Aeromexico (AM)
JFK New York United States
Flight JFK to BOS
BOS Boston United States
Contact Airlines It may not operate on the date requested
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 06:10
4 A12
Arrival Logan International Airport
IATA: BOSICAO: KBOS
Scheduled 07:37
A A4
AM4112 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 5 minutes
  • Flight Distance: 300 kms / 186 miles
Airline
  • Aeromexico
  • IATA: AM
  • ICAO: AMX
  • Operating Days: Monday, Tuesday, Wednesday, Friday, Saturday, Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 1.9 tons
  • Passenger classes: Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: Embraer 175
  • Callsign: AMX4112
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Monday 2025-12-29 17:19 PM
  • Current Time in Boston: Monday 2025-12-29 17:19 PM

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Aeromexico Flight AM4112 FAQs

What is the scheduled flight duration for Aeromexico AM4112 flight?

On average, nonstop flight takes 1 hour(s) 5 minutes, with the flight distance of 300 km (186 miles).

What type of aircraft is used for the Aeromexico AM4112 flight?

All Aeromexico AM4112 flights are operated using Embraer 175 aircraft.

Which terminal the flight Aeromexico AM4112 is arriving at?

Flight Aeromexico AM4112 arrives in Logan International Airport at Terminal A.

How many Aeromexico AM4112 flights are operated a week?

6 flights per week. The Flight Aeromexico AM4112 is operated on Monday, Tuesday, Wednesday, Friday, Saturday, Sunday.