Air India AI9448 Flight Status Today

International flight Air India AI9448 takes off from Bengaluru (BLR) India to Hondo (HDO) United States. It's operated by Air India. The plane leaves Kempegowda International Airport at 09:50 Asia/Kolkata. The flight is expected to land at South Texas Regional Airport at Hondo at 13:00 America/Chicago. The flight will last about 3 hours 10 minutes.

AI9448 - AIC9448 Air India (AI)
BLR Bengaluru India
Flight BLR to HDO
HDO Hondo United States
Contact Airlines It may not operate on the date requested
Departure Kempegowda International Airport
IATA: BLRICAO: VOBL
Scheduled 09:50
2 None
Arrival South Texas Regional Airport at Hondo
IATA: HDOICAO: KHDO
Scheduled 13:00
None None
AI9448 Detail
  • Type: International Flight
  • Flight Duration: 3 hours 10 minutes
  • Flight Distance: 15283 kms / 9497 miles
Airline
  • Air India
  • IATA: AI
  • ICAO: AIC
  • Operating Days: Monday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: None
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: America/Chicago
  • Current Time in Bengaluru: Monday 2026-03-02 05:57 AM
  • Current Time in Hondo: Sunday 2026-03-01 18:27 PM

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Air India Flight AI9448 FAQs

What is the scheduled flight duration for Air India AI9448 flight?

On average, nonstop flight takes 3 hour(s) 10 minutes, with the flight distance of 15283 km (9497 miles).

What type of aircraft is used for the Air India AI9448 flight?

All Air India AI9448 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Air India AI9448 flights are operated a week?

1 flights per week. The Flight Air India AI9448 is operated on Monday.