Air India AI9409 Flight Status Today

Domestic flight Air India AI9409 takes off from Vishakhapatnam (VTZ) India to Hyderabad (HYD) India. It's operated by Air India. The plane leaves Vishakhapatnam Airport at 21:35 29 December 2025 Asia/Kolkata. The flight is expected to land at Rajiv Gandhi International Airport at 22:55 29 December 2025 Asia/Kolkata. The flight will last about 1 hours 20 minutes.

Current status of AI9409 is Scheduled On time Expected Depart in 12 hours, 25 minutes

AI9409 - AIC9409 Air India (AI)
VTZ Vishakhapatnam India
Flight VTZ to HYD
HYD Hyderabad India
Scheduled On time Expected Depart in 12 hours, 25 minutes
Departure Vishakhapatnam Airport
IATA: VTZICAO: VEVZ
Scheduled 21:35 29 December 2025
None None
Arrival Rajiv Gandhi International Airport
IATA: HYDICAO: VOHS
Scheduled 22:55 29 December 2025
None None
AI9409 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 20 minutes
  • Flight Distance: 512 kms / 318 miles
Airline
  • Air India
  • IATA: AI
  • ICAO: AIC
  • Operating Days: Wednesday
Passenger Services
  • Service type: N/A
  • Seats: N/A
  • Freight capacity: N/A
  • Passenger classes: N/A
More Detail
  • Aircraft: Boeing 737MAX 8 Passenger
  • Callsign: N/A
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Vishakhapatnam: Monday 2025-12-29 09:10 AM
  • Current Time in Hyderabad: Monday 2025-12-29 09:10 AM

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Air India Flight AI9409 FAQs

What is the scheduled flight duration for Air India AI9409 flight?

On average, nonstop flight takes 1 hour(s) 20 minutes, with the flight distance of 512 km (318 miles).

What is the current status of Air India AI9409 flight?

The current status of flight Air India AI9409 is Scheduled On time.

What type of aircraft is used for the Air India AI9409 flight?

All Air India AI9409 flights are operated using Boeing 737MAX 8 Passenger aircraft.

How many Air India AI9409 flights are operated a week?

1 flights per week. The Flight Air India AI9409 is operated on Wednesday.