Air India AI9402 flight status now

AI9402 - AIC9402 Air India (AI)
CCU Kolkata India
Flight CCU to DIB
DIB Dibrugarh India
Contact Airlines It may not operate on the date requested
Departure Netaji Subhas Chandra Bose Airport
IATA: CCUICAO: VECC
Scheduled 13:55
None None
Arrival Dibrugarh Airport
IATA: DIBICAO: VEMN
Scheduled 15:30
None None
AI9402 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 35 minutes
  • Flight Distance: 853 kms / 530 miles
Airline
  • Air India
  • IATA: AI
  • ICAO: AIC
  • Operating Days: Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320
  • Callsign: None
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Kolkata: Thursday 2025-11-20 03:22 AM
  • Current Time in Dibrugarh: Thursday 2025-11-20 03:22 AM

Domestic flight Air India AI9402 takes off from Kolkata (CCU) India to Dibrugarh (DIB) India. It's operated by Air India. The plane leaves Netaji Subhas Chandra Bose Airport at 13:55 Asia/Kolkata. The flight is expected to land at Dibrugarh Airport at 15:30 Asia/Kolkata. The flight will last about 1 hours 35 minutes.

Similar flight route from Kolkata (CCU) to Dibrugarh (DIB)

Airline Flight no Departure Arrival
IndiGo 6E893
IndiGo 		20/11/2025
07:15 		1 hours 30 minutes
08:45
IndiGo 6E6103
IndiGo 		20/11/2025
13:45 		1 hours 30 minutes
15:15

Frequently asked questions, answered

How long is the flight from Kolkata to Dibrugarh?

On average, nonstop flight takes 1 hour(s) 35 minutes, with the flight distance of 853 km (530 miles).

What type of aircraft is used for the Air India AI9402 flight?

All Air India AI9402 flights are operated using Airbus A320 aircraft.

How many Air India AI9402 flights are operated a week?

1 flights per week. The Flight Air India AI9402 is operated on Sunday.