Air India AI9258 Flight Status Today

International flight Air India AI9258 takes off from Kuwait (KWI) Kuwait to Mangalore (IXE) India. It's operated by Air India. The plane leaves Kuwait International Airport at 01:40 Asia/Kuwait. The flight is expected to land at Mangalore Airport at 08:50 Asia/Kolkata. The flight will last about 4 hours 40 minutes.

AI9258 - AIC9258 Air India (AI)
KWI Kuwait Kuwait
Flight KWI to IXE
IXE Mangalore India
Contact Airlines It may not operate on the date requested
Departure Kuwait International Airport
IATA: KWIICAO: OKBK
Scheduled 01:40
1 None
Arrival Mangalore Airport
IATA: IXEICAO: VOML
Scheduled 08:50
None None
AI9258 Detail
  • Type: International Flight
  • Flight Duration: 4 hours 40 minutes
  • Flight Distance: 3313 kms / 2058 miles
Airline
  • Air India
  • IATA: AI
  • ICAO: AIC
  • Operating Days: Wednesday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737-800 (winglets) Passenger/BBJ2
  • Callsign: None
  • Departure Timezone: Asia/Kuwait
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Kuwait: Tuesday 2026-02-10 19:35 PM
  • Current Time in Mangalore: Tuesday 2026-02-10 22:05 PM

Flight routes similar to Air India AI9258

Airline Flight no Departure Arrival
Air India Express IX894
Air India Express 		10/02/2026
11:15 		4 hours 55 minutes
18:40

Air India Flight AI9258 FAQs

What is the scheduled flight duration for Air India AI9258 flight?

On average, nonstop flight takes 4 hour(s) 40 minutes, with the flight distance of 3313 km (2058 miles).

What type of aircraft is used for the Air India AI9258 flight?

All Air India AI9258 flights are operated using Boeing 737-800 (winglets) Passenger/BBJ2 aircraft.

How many Air India AI9258 flights are operated a week?

1 flights per week. The Flight Air India AI9258 is operated on Wednesday.