Air India AI7789 Flight Status Today

International flight Air India AI7789 takes off from New York (JFK) United States to Bogota (BOG) Colombia. It's operated by Air India. The plane leaves John F. Kennedy International Airport at 15:35 America/New_York. The flight is expected to land at El Dorado International Airport at 20:30 America/Bogota. The flight will last about 5 hours 44 minutes.

AI7789 - AIC7789 Air India (AI)
JFK New York United States
Flight JFK to BOG
BOG Bogota Colombia
Contact Airlines It may not operate on the date requested
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 15:35
4 None
Arrival El Dorado International Airport
IATA: BOGICAO: SKBO
Scheduled 20:30
1 None
AI7789 Detail
  • Type: International Flight
  • Flight Duration: 5 hours 44 minutes
  • Flight Distance: 3981 kms / 2474 miles
Airline
  • Air India
  • IATA: AI
  • ICAO: AIC
  • Operating Days: Monday, Tuesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A320neo
  • Callsign: None
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Bogota
  • Current Time in New York: Thursday 2026-04-09 05:00 AM
  • Current Time in Bogota: Thursday 2026-04-09 04:00 AM

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Air India Flight AI7789 FAQs

What is the scheduled flight duration for Air India AI7789 flight?

On average, nonstop flight takes 5 hour(s) 44 minutes, with the flight distance of 3981 km (2474 miles).

What type of aircraft is used for the Air India AI7789 flight?

All Air India AI7789 flights are operated using Airbus A320neo aircraft.

Which terminal the flight Air India AI7789 is arriving at?

Flight Air India AI7789 arrives in El Dorado International Airport at Terminal 1.

How many Air India AI7789 flights are operated a week?

6 flights per week. The Flight Air India AI7789 is operated on Monday, Tuesday, Thursday, Friday, Saturday, Sunday.