Air India AI7780 Flight Status Today

International flight Air India AI7780 takes off from Brussels (BRU) Belgium to Warsaw (WAW) Poland. It's operated by Air India. The plane leaves Brussels Airport at 07:50 Europe/Brussels. The flight is expected to land at Frederic Chopin Airport at 09:50 Europe/Warsaw. The flight will last about 1 hours 57 minutes.

AI7780 - AIC7780 Air India (AI)
BRU Brussels Belgium
Flight BRU to WAW
WAW Warsaw Poland
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Brussels Airport
IATA: BRUICAO: EBBR
Scheduled 07:50
None None
Arrival Frederic Chopin Airport
IATA: WAWICAO: EPWA
Scheduled 09:50
None None
AI7780 Detail
  • Type: International Flight
  • Flight Duration: 1 hours 57 minutes
  • Flight Distance: 1150 kms / 715 miles
Airline
  • Air India
  • IATA: AI
  • ICAO: AIC
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer 195 and Legacy 1000
  • Callsign: None
  • Departure Timezone: Europe/Brussels
  • Arrival Timezone: Europe/Warsaw
  • Current Time in Brussels: Sunday 2026-02-08 20:54 PM
  • Current Time in Warsaw: Sunday 2026-02-08 20:54 PM

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Air India Flight AI7780 FAQs

What is the scheduled flight duration for Air India AI7780 flight?

On average, nonstop flight takes 1 hour(s) 57 minutes, with the flight distance of 1150 km (715 miles).

What type of aircraft is used for the Air India AI7780 flight?

All Air India AI7780 flights are operated using Embraer 195 and Legacy 1000 aircraft.