Air India AI7280 Flight Status Today

International flight Air India AI7280 takes off from Johannesburg (JNB) South Africa to Saint Denis de la Reunion (RUN) Reunion. It's operated by Air India. The plane leaves O.R. Tambo International Airport at 14:55 Africa/Johannesburg. The flight is expected to land at Reunion Roland Garros Airport at 20:45 Indian/Reunion. The flight will last about 3 hours 50 minutes.

AI7280 - AIC7280 Air India (AI)
JNB Johannesburg South Africa
Flight JNB to RUN
RUN Saint Denis de la Reunion Reunion
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 29-December-2020
Departure O.R. Tambo International Airport
IATA: JNBICAO: FAOR
Scheduled 14:55
A None
Arrival Reunion Roland Garros Airport
IATA: RUNICAO: FMEE
Scheduled 20:45
None None
AI7280 Detail
  • Type: International Flight
  • Flight Duration: 3 hours 50 minutes
  • Flight Distance: 2839 kms / 1764 miles
Airline
  • Air India
  • IATA: AI
  • ICAO: AIC
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 162
  • Freight capacity: 17.8 tons
  • Passenger classes: Economy
More Detail
  • Aircraft: Boeing 737-800 Passenger
  • Callsign: AIC7280
  • Departure Timezone: Africa/Johannesburg
  • Arrival Timezone: Indian/Reunion
  • Current Time in Johannesburg: Friday 2026-01-02 02:39 AM
  • Current Time in Saint Denis de la Reunion: Friday 2026-01-02 04:39 AM

Flight routes similar to Air India AI7280

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23:45 		3 hours 55 minutes
05:40
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06:55

Air India Flight AI7280 FAQs

What is the scheduled flight duration for Air India AI7280 flight?

On average, nonstop flight takes 3 hour(s) 50 minutes, with the flight distance of 2839 km (1764 miles).

What type of aircraft is used for the Air India AI7280 flight?

All Air India AI7280 flights are operated using Boeing 737-800 Passenger aircraft.