Air India AI724 Flight Status Today

Domestic flight Air India AI724 takes off from Bagdogra (IXB) India to Kolkata (CCU) India. It's operated by Air India. The plane leaves Bagdogra Airport at 11:35 Asia/Kolkata. The flight is expected to land at Netaji Subhas Chandra Bose Airport at 12:45 Asia/Kolkata. The flight will last about 1 hours 10 minutes.

AI724 - AIC724 Air India (AI)
IXB Bagdogra India
Flight IXB to CCU
CCU Kolkata India
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 21-September-2019
Departure Bagdogra Airport
IATA: IXBICAO: VEBD
Scheduled 11:35
None None
Arrival Netaji Subhas Chandra Bose Airport
IATA: CCUICAO: VECC
Scheduled 12:45
None None
AI724 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 10 minutes
  • Flight Distance: 448 kms / 278 miles
Airline
  • Air India
  • IATA: AI
  • ICAO: AIC
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 122
  • Freight capacity: 6.7 tons
  • Passenger classes: Economy, Premium Economy
More Detail
  • Aircraft: Airbus A319
  • Callsign: AIC724
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Bagdogra: Sunday 2026-01-18 19:59 PM
  • Current Time in Kolkata: Sunday 2026-01-18 19:59 PM

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Air India Flight AI724 FAQs

What is the scheduled flight duration for Air India AI724 flight?

On average, nonstop flight takes 1 hour(s) 10 minutes, with the flight distance of 448 km (278 miles).

What type of aircraft is used for the Air India AI724 flight?

All Air India AI724 flights are operated using Airbus A319 aircraft.