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Air India AI7175 Flight Status Today
Domestic flight Air India AI7175 takes off from Melbourne (MEL) Australia to Hobart (HBA) Australia. It's operated by Air India. The plane leaves Melbourne Tullamarine Airport at 22:30 01 January 2026 Australia/Sydney. The flight is expected to land at Hobart International Airport at 23:50 01 January 2026 Australia/Hobart. The flight will last about 1 hours 20 minutes.
Current status of AI7175 is Scheduled On time Expected Depart in 14 hours, 5 minutes
- Type: Domestic Flight
- Code Shares: QR 6310, SQ 6586
- Flight Duration: 1 hours 20 minutes
- Flight Distance: 616 kms / 383 miles
- Air India
- IATA: AI
- ICAO: AIC
- Operating Days: Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday
- Service type: N/A
- Seats: N/A
- Freight capacity: N/A
- Passenger classes: N/A
- Aircraft: Boeing 737-800 (winglets) Passenger/BBJ2
- Callsign: N/A
- Departure Timezone: Australia/Sydney
- Arrival Timezone: Australia/Hobart
- Current Time in Melbourne: Thursday 2026-01-01 08:25 AM
- Current Time in Hobart: Thursday 2026-01-01 08:25 AM
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Air India Flight AI7175 FAQs
What is the scheduled flight duration for Air India AI7175 flight?
On average, nonstop flight takes 1 hour(s) 20 minutes, with the flight distance of 616 km (383 miles).
What is the current status of Air India AI7175 flight?
The current status of flight Air India AI7175 is Scheduled On time.
What type of aircraft is used for the Air India AI7175 flight?
All Air India AI7175 flights are operated using Boeing 737-800 (winglets) Passenger/BBJ2 aircraft.
When does the flight Air India AI7175 arrive?
Flight Air India AI7175 arrives at 23:50.
Which terminal the flight Air India AI7175 is arriving at?
Flight Air India AI7175 arrives in Hobart International Airport at Terminal D.
How many Air India AI7175 flights are operated a week?
6 flights per week. The Flight Air India AI7175 is operated on Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.
