Air India AI198 Flight Status Today

International flight Air India AI198 takes off from Shannon (SNN) Ireland to Delhi (DEL) India. It's operated by Air India. The plane leaves Shannon Airport at 11:10 Europe/Dublin. The flight is expected to land at Indira Gandhi International Airport at 04:01 Asia/Kolkata. The flight will last about 6 hours 48 minutes.

AI198 - AIC198 Air India (AI)
SNN Shannon Ireland
Flight SNN to DEL
DEL Delhi India
Contact Airlines It may not operate on the date requested
Departure Shannon Airport
IATA: SNNICAO: EINN
Scheduled 11:10
None None
Arrival Indira Gandhi International Airport
IATA: DELICAO: VIDP
Scheduled 04:01
None None
AI198 Detail
  • Type: International Flight
  • Flight Duration: 6 hours 48 minutes
  • Flight Distance: 7280 kms / 4524 miles
Airline
  • Air India
  • IATA: AI
  • ICAO: AIC
  • Operating Days:
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A350-941
  • Callsign: AIC198
  • Departure Timezone: Europe/Dublin
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Shannon: Thursday 2026-04-16 21:56 PM
  • Current Time in Delhi: Friday 2026-04-17 02:26 AM

Air India Flight AI198 FAQs

What is the scheduled flight duration for Air India AI198 flight?

On average, nonstop flight takes 6 hour(s) 48 minutes, with the flight distance of 7280 km (4524 miles).

What type of aircraft is used for the Air India AI198 flight?

All Air India AI198 flights are operated using Airbus A350-941 aircraft.