Air India AI1788 Flight Status Today

Domestic flight Air India AI1788 takes off from Port Blair (IXZ) India to Kolkata (CCU) India. It's operated by Air India. The plane leaves Port Blair Airport at 09:50 Asia/Kolkata. The flight is expected to land at Netaji Subhas Chandra Bose Airport at 12:00 Asia/Kolkata. The flight will last about 2 hours 20 minutes.

AI1788 - AIC1788 Air India (AI)
IXZ Port Blair India
Flight IXZ to CCU
CCU Kolkata India
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 16-August-2020
Departure Port Blair Airport
IATA: IXZICAO: VOPB
Scheduled 09:50
Arrival Netaji Subhas Chandra Bose Airport
IATA: CCUICAO: VECC
Scheduled 12:00
AI1788 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 20 minutes
  • Flight Distance: 1299 kms / 807 miles
Airline
  • Air India
  • IATA: AI
  • ICAO: AIC
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft:
  • Callsign: None
  • Departure Timezone: Asia/Kolkata
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Port Blair: Monday 2025-12-29 20:00 PM
  • Current Time in Kolkata: Monday 2025-12-29 20:00 PM

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Air India Flight AI1788 FAQs

What is the scheduled flight duration for Air India AI1788 flight?

On average, nonstop flight takes 2 hour(s) 20 minutes, with the flight distance of 1299 km (807 miles).