Air France AF9158 Flight Status Today

Domestic flight Air France AF9158 takes off from New York (JFK) United States to Washington (DCA) United States. It's operated by Air France. The plane leaves John F. Kennedy International Airport at 19:30 America/New_York. The flight is expected to land at Ronald Reagan National Airport at 20:59 America/New_York. The flight will last about 1 hours 36 minutes.

AF9158 - AFR9158 Air France (AF)
JFK New York United States
Flight JFK to DCA
DCA Washington United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 19:30
4
Arrival Ronald Reagan National Airport
IATA: DCAICAO: KDCA
Scheduled 20:59
B
AF9158 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 36 minutes
  • Flight Distance: 342 kms / 213 miles
Airline
  • Air France
  • IATA: AF
  • ICAO: AFR
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 1.9 tons
  • Passenger classes: First Class, Economy, Business Class, Premium Economy
More Detail
  • Aircraft: CRJ9
  • Callsign: AFR9158
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in New York: Thursday 2026-04-30 01:53 AM
  • Current Time in Washington: Thursday 2026-04-30 01:53 AM

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Air France Flight AF9158 FAQs

What is the scheduled flight duration for Air France AF9158 flight?

On average, nonstop flight takes 1 hour(s) 36 minutes, with the flight distance of 342 km (213 miles).

What type of aircraft is used for the Air France AF9158 flight?

All Air France AF9158 flights are operated using CRJ9 aircraft.

Which terminal the flight Air France AF9158 is arriving at?

Flight Air France AF9158 arrives in Ronald Reagan National Airport at Terminal B.