Air France AF9088 Flight Status Today

International flight Air France AF9088 takes off from Rome (FCO) Italy to New York (JFK) United States. It's operated by Air France. The plane leaves Leonardo da Vinci-Fiumicino Airport at 14:25 Europe/Rome. The flight is expected to land at John F. Kennedy International Airport at 18:20 America/New_York. The flight will last about 9 hours 55 minutes.

AF9088 - AFR9088 Air France (AF)
FCO Rome Italy
Flight FCO to JFK
JFK New York United States
Contact Airlines It may not operate on the date requested
Departure Leonardo da Vinci-Fiumicino Airport
IATA: FCOICAO: LIRF
Scheduled 14:25
3 E23
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 18:20
4 B39
AF9088 Detail
  • Type: International Flight
  • Flight Duration: 9 hours 55 minutes
  • Flight Distance: 6885 kms / 4278 miles
Airline
  • Air France
  • IATA: AF
  • ICAO: AFR
  • Operating Days: Friday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A330-300
  • Callsign: None
  • Departure Timezone: Europe/Rome
  • Arrival Timezone: America/New_York
  • Current Time in Rome: Thursday 2026-01-01 11:33 AM
  • Current Time in New York: Thursday 2026-01-01 05:33 AM

Flight routes similar to Air France AF9088

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Air France Flight AF9088 FAQs

What is the scheduled flight duration for Air France AF9088 flight?

On average, nonstop flight takes 9 hour(s) 55 minutes, with the flight distance of 6885 km (4278 miles).

What type of aircraft is used for the Air France AF9088 flight?

All Air France AF9088 flights are operated using Airbus A330-300 aircraft.

Which terminal the flight Air France AF9088 is arriving at?

Flight Air France AF9088 arrives in John F. Kennedy International Airport at Terminal 4.

How many Air France AF9088 flights are operated a week?

1 flights per week. The Flight Air France AF9088 is operated on Friday.