Air France AF9012 Flight Status Today

Domestic flight Air France AF9012 takes off from Boston (BOS) United States to Columbus (CMH) United States. It's operated by Air France. The plane leaves Logan International Airport at 15:05 America/New_York. The flight is expected to land at John Glenn Columbus International Airport at 17:28 America/New_York. The flight will last about 1 hours 46 minutes.

AF9012 - AFR9012 Air France (AF)
BOS Boston United States
Flight BOS to CMH
CMH Columbus United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 07-March-2020
Departure Logan International Airport
IATA: BOSICAO: KBOS
Scheduled 15:05
A
Arrival John Glenn Columbus International Airport
IATA: CMHICAO: KCMH
Scheduled 17:28
C
AF9012 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 46 minutes
  • Flight Distance: 1029 kms / 639 miles
Airline
  • Air France
  • IATA: AF
  • ICAO: AFR
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 50
  • Freight capacity: 1.5 tons
  • Passenger classes: First Class, Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: E75
  • Callsign: AFR9012
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Boston: Saturday 2026-02-07 07:31 AM
  • Current Time in Columbus: Saturday 2026-02-07 07:31 AM

Flight routes similar to Air France AF9012

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21:01

Air France Flight AF9012 FAQs

What is the scheduled flight duration for Air France AF9012 flight?

On average, nonstop flight takes 1 hour(s) 46 minutes, with the flight distance of 1029 km (639 miles).

What type of aircraft is used for the Air France AF9012 flight?

All Air France AF9012 flights are operated using E75 aircraft.

Which terminal the flight Air France AF9012 is arriving at?

Flight Air France AF9012 arrives in John Glenn Columbus International Airport at Terminal C.