Air France AF8908 Flight Status Today

Domestic flight Air France AF8908 takes off from Boston (BOS) United States to New York (JFK) United States. It's operated by Air France. The plane leaves Logan International Airport at 13:45 America/New_York. The flight is expected to land at John F. Kennedy International Airport at 15:12 America/New_York. The flight will last about 1 hours 27 minutes.

AF8908 - AFR8908 Air France (AF)
BOS Boston United States
Flight BOS to JFK
JFK New York United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 01-April-2020
Departure Logan International Airport
IATA: BOSICAO: KBOS
Scheduled 13:45
A A10
Arrival John F. Kennedy International Airport
IATA: JFKICAO: KJFK
Scheduled 15:12
4 B47
AF8908 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 27 minutes
  • Flight Distance: 300 kms / 186 miles
Airline
  • Air France
  • IATA: AF
  • ICAO: AFR
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 1.9 tons
  • Passenger classes: First Class, Economy, Business Class, Premium Economy
More Detail
  • Aircraft: CRJ9
  • Callsign: AFR8908
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Boston: Wednesday 2025-12-31 10:45 AM
  • Current Time in New York: Wednesday 2025-12-31 10:45 AM

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Air France Flight AF8908 FAQs

What is the scheduled flight duration for Air France AF8908 flight?

On average, nonstop flight takes 1 hour(s) 27 minutes, with the flight distance of 300 km (186 miles).

What type of aircraft is used for the Air France AF8908 flight?

All Air France AF8908 flights are operated using CRJ9 aircraft.

Which terminal the flight Air France AF8908 is arriving at?

Flight Air France AF8908 arrives in John F. Kennedy International Airport at Terminal 4.