Air France AF7147 Flight Status Today

Domestic flight Air France AF7147 takes off from Upington (UTN) South Africa to Johannesburg (JNB) South Africa. It's operated by Air France. The plane leaves Upington Airport at 12:20 Africa/Johannesburg. The flight is expected to land at O.R. Tambo International Airport at 13:40 Africa/Johannesburg. The flight will last about 1 hours 20 minutes.

AF7147 - AFR7147 Air France (AF)
UTN Upington South Africa
Flight UTN to JNB
JNB Johannesburg South Africa
Contact Airlines It may not operate on the date requested
Departure Upington Airport
IATA: UTNICAO: FAUP
Scheduled 12:20
None None
Arrival O.R. Tambo International Airport
IATA: JNBICAO: FAOR
Scheduled 13:40
B E7
AF7147 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 20 minutes
  • Flight Distance: 736 kms / 457 miles
Airline
  • Air France
  • IATA: AF
  • ICAO: AFR
  • Operating Days: Friday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Embraer RJ135 and Legacy 600/650
  • Callsign: None
  • Departure Timezone: Africa/Johannesburg
  • Arrival Timezone: Africa/Johannesburg
  • Current Time in Upington: Monday 2025-12-29 15:25 PM
  • Current Time in Johannesburg: Monday 2025-12-29 15:25 PM

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Air France Flight AF7147 FAQs

What is the scheduled flight duration for Air France AF7147 flight?

On average, nonstop flight takes 1 hour(s) 20 minutes, with the flight distance of 736 km (457 miles).

What type of aircraft is used for the Air France AF7147 flight?

All Air France AF7147 flights are operated using Embraer RJ135 and Legacy 600/650 aircraft.

Which terminal the flight Air France AF7147 is arriving at?

Flight Air France AF7147 arrives in O.R. Tambo International Airport at Terminal B.

How many Air France AF7147 flights are operated a week?

1 flights per week. The Flight Air France AF7147 is operated on Friday.