Air France AF7108 Flight Status Today

Domestic flight Air France AF7108 takes off from Johannesburg (JNB) South Africa to Upington (UTN) South Africa. It's operated by Air France. The plane leaves O.R. Tambo International Airport at 15:55 Africa/Johannesburg. The flight is expected to land at Upington Airport at 17:30 Africa/Johannesburg. The flight will last about 1 hours 35 minutes.

AF7108 - AFR7108 Air France (AF)
JNB Johannesburg South Africa
Flight JNB to UTN
UTN Upington South Africa
Contact Airlines It may not operate on the date requested
Departure O.R. Tambo International Airport
IATA: JNBICAO: FAOR
Scheduled 15:55
B None
Arrival Upington Airport
IATA: UTNICAO: FAUP
Scheduled 17:30
None None
AF7108 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 35 minutes
  • Flight Distance: 736 kms / 457 miles
Airline
  • Air France
  • IATA: AF
  • ICAO: AFR
  • Operating Days: Friday
Passenger Services
  • Service type: Passenger (surface)
  • Seats: 101
  • Freight capacity: 0 tons
  • Passenger classes: First Class, Economy, Business Class, Premium Economy
More Detail
  • Aircraft: Embraer RJ135 and Legacy 600/650
  • Callsign: AFR7108
  • Departure Timezone: Africa/Johannesburg
  • Arrival Timezone: Africa/Johannesburg
  • Current Time in Johannesburg: Wednesday 2025-12-31 15:38 PM
  • Current Time in Upington: Wednesday 2025-12-31 15:38 PM

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Air France Flight AF7108 FAQs

What is the scheduled flight duration for Air France AF7108 flight?

On average, nonstop flight takes 1 hour(s) 35 minutes, with the flight distance of 736 km (457 miles).

What type of aircraft is used for the Air France AF7108 flight?

All Air France AF7108 flights are operated using Embraer RJ135 and Legacy 600/650 aircraft.

How many Air France AF7108 flights are operated a week?

1 flights per week. The Flight Air France AF7108 is operated on Friday.