Air France AF5947 Flight Status Today

Domestic flight Air France AF5947 takes off from Boston (BOS) United States to Fort Myers (RSW) United States. It's operated by Air France. The plane leaves Logan International Airport at 16:01 America/New_York. The flight is expected to land at Southwest Florida International Airport at 19:43 America/New_York. The flight will last about 3 hours 42 minutes.

AF5947 - AFR5947 Air France (AF)
BOS Boston United States
Flight BOS to RSW
RSW Fort Myers United States
Contact Airlines It may not operate on the date requested
Departure Logan International Airport
IATA: BOSICAO: KBOS
Scheduled 16:01
A A7
Arrival Southwest Florida International Airport
IATA: RSWICAO: KRSW
Scheduled 19:43
None C9
AF5947 Detail
  • Type: Domestic Flight
  • Flight Duration: 3 hours 42 minutes
  • Flight Distance: 2011 kms / 1250 miles
Airline
  • Air France
  • IATA: AF
  • ICAO: AFR
  • Operating Days: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday
Passenger Services
  • Service type: Normal passenger
  • Seats: 76
  • Freight capacity: 1.9 tons
  • Passenger classes: First Class, Economy, Business Class, Premium Economy
More Detail
  • Aircraft: Boeing 737-900 Passenger (Scimitar Winglets)
  • Callsign: AFR5947
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Boston: Tuesday 2026-02-17 12:03 PM
  • Current Time in Fort Myers: Tuesday 2026-02-17 12:03 PM

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Air France Flight AF5947 FAQs

What is the scheduled flight duration for Air France AF5947 flight?

On average, nonstop flight takes 3 hour(s) 42 minutes, with the flight distance of 2011 km (1250 miles).

What type of aircraft is used for the Air France AF5947 flight?

All Air France AF5947 flights are operated using Boeing 737-900 Passenger (Scimitar Winglets) aircraft.

How many Air France AF5947 flights are operated a week?

7 flights per week. The Flight Air France AF5947 is operated on Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday .