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Air France AF5475 Flight Status Today
International flight Air France AF5475 takes off from Amsterdam (AMS) Netherlands to Hyderabad (HYD) India. It's operated by Air France. The plane leaves Amsterdam Airport Schiphol at 11:30 18 January 2026 Europe/Amsterdam. The flight is expected to land at Rajiv Gandhi International Airport at 01:00 19 January 2026 Asia/Kolkata. The flight will last about 8 hours 30 minutes.
Current status of AF5475 is Scheduled On time Expected Depart in 2 hours, 16 minutes
- Type: International Flight
- Code Shares: DL 9218
- Flight Duration: 8 hours 30 minutes
- Flight Distance: 7402 kms / 4599 miles
- Air France
- IATA: AF
- ICAO: AFR
- Operating Days: Monday, Tuesday, Wednesday, Thursday, Saturday, Sunday
- Service type: Normal passenger
- Seats: 100
- Freight capacity: 5.1 tons
- Passenger classes: First Class, Economy, Business Class, Shuttle, Premium Economy
- Aircraft: Boeing 787-9
- Callsign: AFR5475
- Departure Timezone: Europe/Amsterdam
- Arrival Timezone: Asia/Kolkata
- Current Time in Amsterdam: Sunday 2026-01-18 09:14 AM
- Current Time in Hyderabad: Sunday 2026-01-18 13:44 PM
Flight routes similar to Air France AF5475
| Airline | Flight no | Departure | Arrival |
|---|---|---|---|
|
DL9218 Delta |
18/01/2026 11:30 |
0 minutes 01:00 |
Air France Flight AF5475 FAQs
What is the scheduled flight duration for Air France AF5475 flight?
On average, nonstop flight takes 8 hour(s) 30 minutes, with the flight distance of 7402 km (4599 miles).
What is the current status of Air France AF5475 flight?
The current status of flight Air France AF5475 is Scheduled On time.
What type of aircraft is used for the Air France AF5475 flight?
All Air France AF5475 flights are operated using Boeing 787-9 aircraft.
How many Air France AF5475 flights are operated a week?
6 flights per week. The Flight Air France AF5475 is operated on Monday, Tuesday, Wednesday, Thursday, Saturday, Sunday.
