Air France AF4975 Flight Status Today

Domestic flight Air France AF4975 takes off from Kaliningrad (KGD) Russia to Moscow (SVO) Russia. It's operated by Air France. The plane leaves Khrabrovo Airport at 03:00 Europe/Kaliningrad. The flight is expected to land at Sheremetyevo International Airport at 06:05 Europe/Moscow. The flight will last about 1 hours 32 minutes.

AF4975 - AFR4975 Air France (AF)
KGD Kaliningrad Russia
Flight KGD to SVO
SVO Moscow Russia
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 10-October-2020
Departure Khrabrovo Airport
IATA: KGDICAO: UMKK
Scheduled 03:00
A
Arrival Sheremetyevo International Airport
IATA: SVOICAO: UUEE
Scheduled 06:05
AF4975 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 32 minutes
  • Flight Distance: 1070 kms / 665 miles
Airline
  • Air France
  • IATA: AF
  • ICAO: AFR
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 158
  • Freight capacity: 0 tons
  • Passenger classes: First Class, Economy, Business Class
More Detail
  • Aircraft: Airbus A320
  • Callsign: AFR4975
  • Departure Timezone: Europe/Kaliningrad
  • Arrival Timezone: Europe/Moscow
  • Current Time in Kaliningrad: Friday 2026-05-01 08:42 AM
  • Current Time in Moscow: Friday 2026-05-01 09:42 AM

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Air France Flight AF4975 FAQs

What is the scheduled flight duration for Air France AF4975 flight?

On average, nonstop flight takes 1 hour(s) 32 minutes, with the flight distance of 1070 km (665 miles).

What type of aircraft is used for the Air France AF4975 flight?

All Air France AF4975 flights are operated using Airbus A320 aircraft.