Air Canada AC8395 Flight Status Today

Domestic flight Air Canada AC8395 takes off from Calgary (YYC) Canada to Kelowna (YLW) Canada. It's operated by Air Canada. The plane leaves Calgary International Airport at 15:30 America/Edmonton. The flight is expected to land at Kelowna International Airport at 15:37 America/Vancouver. The flight will last about 1 hours 6 minutes.

AC8395 - ACA8395 Air Canada (AC)
YYC Calgary Canada
Flight YYC to YLW
YLW Kelowna Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 01-May-2022
Departure Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled 15:30
None A15
Arrival Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 15:37
None G5
AC8395 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 6 minutes
  • Flight Distance: 403 kms / 250 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 74
  • Freight capacity: 1.6 tons
  • Passenger classes: Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: De Havilland (Bombardier) DHC-8-400 Dash 8Q
  • Callsign: F-CYLW4
  • Departure Timezone: America/Edmonton
  • Arrival Timezone: America/Vancouver
  • Current Time in Calgary: Thursday 2026-04-30 02:14 AM
  • Current Time in Kelowna: Thursday 2026-04-30 01:14 AM

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Air Canada Flight AC8395 FAQs

What is the scheduled flight duration for Air Canada AC8395 flight?

On average, nonstop flight takes 1 hour(s) 6 minutes, with the flight distance of 403 km (250 miles).

What type of aircraft is used for the Air Canada AC8395 flight?

All Air Canada AC8395 flights are operated using De Havilland (Bombardier) DHC-8-400 Dash 8Q aircraft.