Air Canada AC7489 Flight Status Today

International flight Air Canada AC7489 takes off from New York (LGA) United States to Toronto (YYZ) Canada. It's operated by Air Canada. The plane leaves LaGuardia Airport at 18:40 America/New_York. The flight is expected to land at Pearson International Airport at 20:14 America/Toronto. The flight will last about 1 hours 34 minutes.

AC7489 - ACA7489 Air Canada (AC)
LGA New York United States
Flight LGA to YYZ
YYZ Toronto Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 01-May-2022
Departure LaGuardia Airport
IATA: LGAICAO: KLGA
Scheduled 18:40
B None
Arrival Pearson International Airport
IATA: YYZICAO: CYYZ
Scheduled 20:14
1 None
AC7489 Detail
  • Type: International Flight
  • Flight Duration: 1 hours 34 minutes
  • Flight Distance: 573 kms / 356 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 73
  • Freight capacity: 1.2 tons
  • Passenger classes: First Class, Economy, Business Class, Shuttle
More Detail
  • Aircraft: Embraer 175
  • Callsign: ACA7489
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/Toronto
  • Current Time in New York: Thursday 2026-04-09 07:30 AM
  • Current Time in Toronto: Thursday 2026-04-09 07:30 AM

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Air Canada Flight AC7489 FAQs

What is the scheduled flight duration for Air Canada AC7489 flight?

On average, nonstop flight takes 1 hour(s) 34 minutes, with the flight distance of 573 km (356 miles).

What type of aircraft is used for the Air Canada AC7489 flight?

All Air Canada AC7489 flights are operated using Embraer 175 aircraft.

Which terminal the flight Air Canada AC7489 is arriving at?

Flight Air Canada AC7489 arrives in Pearson International Airport at Terminal 1.