Air Canada AC7143 Flight Status Today

Domestic flight Air Canada AC7143 takes off from Kelowna (YLW) Canada to Calgary (YYC) Canada. It's operated by Air Canada. The plane leaves Kelowna International Airport at 17:36 America/Vancouver. The flight is expected to land at Calgary International Airport at None America/Edmonton. The flight will last about 1 hours 11 minutes.

AC7143 - ACA7143 Air Canada (AC)
YLW Kelowna Canada
Flight YLW to YYC
YYC Calgary Canada
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Kelowna International Airport
IATA: YLWICAO: CYLW
Scheduled 17:36
None None
Arrival Calgary International Airport
IATA: YYCICAO: CYYC
Scheduled None
None None
AC7143 Detail
  • Type: Domestic Flight
  • Flight Duration: 1 hours 11 minutes
  • Flight Distance: 403 kms / 250 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: De Havilland Canada Dash 8-400
  • Callsign: JZA7143
  • Departure Timezone: America/Vancouver
  • Arrival Timezone: America/Edmonton
  • Current Time in Kelowna: Monday 2025-12-29 03:43 AM
  • Current Time in Calgary: Monday 2025-12-29 04:43 AM

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Air Canada Flight AC7143 FAQs

What is the scheduled flight duration for Air Canada AC7143 flight?

On average, nonstop flight takes 1 hour(s) 11 minutes, with the flight distance of 403 km (250 miles).

What type of aircraft is used for the Air Canada AC7143 flight?

All Air Canada AC7143 flights are operated using De Havilland Canada Dash 8-400 aircraft.