Air Canada AC7105 Flight Status Today

International flight Air Canada AC7105 takes off from Toronto (YYZ) Canada to Kingston (KIN) Jamaica. It's operated by Air Canada. The plane leaves Pearson International Airport at America/Toronto. The flight is expected to land at Norman Manley International Airport at 12:33 America/Jamaica. The flight will last about 4 hours 30 minutes.

AC7105 - ACA7105 Air Canada (AC)
YYZ Toronto Canada
Flight YYZ to KIN
KIN Kingston Jamaica
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on
Departure Pearson International Airport
IATA: YYZICAO: CYYZ
Scheduled
Arrival Norman Manley International Airport
IATA: KINICAO: MKJP
Scheduled 12:33
AC7105 Detail
  • Type: International Flight
  • Flight Duration: 4 hours 30 minutes
  • Flight Distance: 2867 kms / 1781 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft:
  • Callsign: None
  • Departure Timezone: America/Toronto
  • Arrival Timezone: America/Jamaica
  • Current Time in Toronto: Wednesday 2026-01-21 02:50 AM
  • Current Time in Kingston: Wednesday 2026-01-21 02:50 AM

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Air Canada Flight AC7105 FAQs

What is the scheduled flight duration for Air Canada AC7105 flight?

On average, nonstop flight takes 4 hour(s) 30 minutes, with the flight distance of 2867 km (1781 miles).