Air Canada AC7088 Flight Status Today

International flight Air Canada AC7088 takes off from Milwaukee (MKE) United States to Toronto (YYZ) Canada. It's operated by Air Canada. The plane leaves General Mitchell International Airport at 20:35 America/Chicago. The flight is expected to land at Pearson International Airport at 22:40 America/Toronto. The flight will last about 0 minutes.

AC7088 - ACA7088 Air Canada (AC)
MKE Milwaukee United States
Flight MKE to YYZ
YYZ Toronto Canada
Contact Airlines It may not operate on the date requested
Departure General Mitchell International Airport
IATA: MKEICAO: KMKE
Scheduled 20:35
None None
Arrival Pearson International Airport
IATA: YYZICAO: CYYZ
Scheduled 22:40
1 F70
AC7088 Detail
  • Type: International Flight
  • Flight Duration: 0 minutes
  • Flight Distance: 677 kms / 421 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: Wednesday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Airbus A321
  • Callsign: T-KRDU126
  • Departure Timezone: America/Chicago
  • Arrival Timezone: America/Toronto
  • Current Time in Milwaukee: Thursday 2026-04-23 12:26 PM
  • Current Time in Toronto: Thursday 2026-04-23 13:26 PM

Air Canada Flight AC7088 FAQs

What is the scheduled flight duration for Air Canada AC7088 flight?

On average, nonstop flight takes 0 minutes, with the flight distance of 677 km (421 miles).

What type of aircraft is used for the Air Canada AC7088 flight?

All Air Canada AC7088 flights are operated using Airbus A321 aircraft.

Which terminal the flight Air Canada AC7088 is arriving at?

Flight Air Canada AC7088 arrives in Pearson International Airport at Terminal 1.

How many Air Canada AC7088 flights are operated a week?

1 flights per week. The Flight Air Canada AC7088 is operated on Wednesday.