Air Canada AC5496 flight status now

AC5496 - ACA5496 Air Canada (AC)
AVL Asheville United States
Flight AVL to EWR
EWR Newark United States
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 18-August-2019
Departure Asheville Regional Airport
IATA: AVLICAO: KAVL
Scheduled 15:15
None None
Arrival Newark Liberty International Airport
IATA: EWRICAO: KEWR
Scheduled 17:16
A 25
AC5496 Detail
  • Type: Domestic Flight
  • Flight Duration: 2 hours 1 minutes
  • Flight Distance: 936 kms / 582 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: Normal passenger
  • Seats: 50
  • Freight capacity: 1 tons
  • Passenger classes: Economy, Shuttle, Premium Economy
More Detail
  • Aircraft: E145
  • Callsign: ACA5496
  • Departure Timezone: America/New_York
  • Arrival Timezone: America/New_York
  • Current Time in Asheville: Thursday 2025-11-20 05:01 AM
  • Current Time in Newark: Thursday 2025-11-20 05:01 AM

Domestic flight Air Canada AC5496 takes off from Asheville (AVL) United States to Newark (EWR) United States. It's operated by Air Canada. The plane leaves Asheville Regional Airport at 15:15 America/New_York. The flight is expected to land at Newark Liberty International Airport at 17:16 America/New_York. The flight will last about 2 hours 1 minutes.

Similar flight route from Asheville (AVL) to Newark (EWR)

Airline Flight no Departure Arrival
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United Airlines UA4179
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Allegiant Air G4216
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GoJet Airlines G74524
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Air Canada AC3787
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United Airlines UA4524
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20/11/2025
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Frequently asked questions, answered

How long is the flight from Asheville to Newark?

On average, nonstop flight takes 2 hour(s) 1 minutes, with the flight distance of 936 km (582 miles).

What type of aircraft is used for the Air Canada AC5496 flight?

All Air Canada AC5496 flights are operated using E145 aircraft.

Which terminal the flight Air Canada AC5496 is arriving at?

Flight Air Canada AC5496 arrives in Newark Liberty International Airport at Terminal A.