Air Canada AC5408 Flight Status Today

International flight Air Canada AC5408 takes off from San Juan (SJU) Puerto Rico to Newark (EWR) United States. It's operated by Air Canada. The plane leaves Luis Munoz Marin International Airport at 07:00 America/Puerto_Rico. The flight is expected to land at Newark Liberty International Airport at 10:15 America/New_York. The flight will last about 4 hours 27 minutes.

AC5408 - ACA5408 Air Canada (AC)
SJU San Juan Puerto Rico
Flight SJU to EWR
EWR Newark United States
Contact Airlines It may not operate on the date requested
Departure Luis Munoz Marin International Airport
IATA: SJUICAO: TJSJ
Scheduled 07:00
B B6
Arrival Newark Liberty International Airport
IATA: EWRICAO: KEWR
Scheduled 10:15
C 101
AC5408 Detail
  • Type: International Flight
  • Flight Duration: 4 hours 27 minutes
  • Flight Distance: 2588 kms / 1608 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: Friday
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 737MAX 9 Passenger
  • Callsign: None
  • Departure Timezone: America/Puerto_Rico
  • Arrival Timezone: America/New_York
  • Current Time in San Juan: Sunday 2026-01-18 21:21 PM
  • Current Time in Newark: Sunday 2026-01-18 20:21 PM

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Air Canada Flight AC5408 FAQs

What is the scheduled flight duration for Air Canada AC5408 flight?

On average, nonstop flight takes 4 hour(s) 27 minutes, with the flight distance of 2588 km (1608 miles).

What type of aircraft is used for the Air Canada AC5408 flight?

All Air Canada AC5408 flights are operated using Boeing 737MAX 9 Passenger aircraft.

Which terminal the flight Air Canada AC5408 is arriving at?

Flight Air Canada AC5408 arrives in Newark Liberty International Airport at Terminal C.

How many Air Canada AC5408 flights are operated a week?

1 flights per week. The Flight Air Canada AC5408 is operated on Friday.