Air Canada AC48 Flight Status Today

International flight Air Canada AC48 takes off from Toronto (YYZ) Canada to Delhi (DEL) India. It's operated by Air Canada. The plane leaves Pearson International Airport at 09:00 America/Toronto. The flight is expected to land at Indira Gandhi International Airport at 09:50 Asia/Kolkata. The flight will last about 15 hours 20 minutes.

AC48 - ACA48 Air Canada (AC)
YYZ Toronto Canada
Flight YYZ to DEL
DEL Delhi India
NO FLIGHTS IN THE LAST 14 DAYS Lasted record on 01-May-2022
Departure Pearson International Airport
IATA: YYZICAO: CYYZ
Scheduled 09:00
1 None
Arrival Indira Gandhi International Airport
IATA: DELICAO: VIDP
Scheduled 09:50
T3 10
AC48 Detail
  • Type: International Flight
  • Flight Duration: 15 hours 20 minutes
  • Flight Distance: 11662 kms / 7246 miles
Airline
  • Air Canada
  • IATA: AC
  • ICAO: ACA
  • Operating Days: NO FLIGHTS IN THE LAST 14 DAYS
Passenger Services
  • Service type: None
  • Seats: None
  • Freight capacity: None
  • Passenger classes: None
More Detail
  • Aircraft: Boeing 777-200LR
  • Callsign: None
  • Departure Timezone: America/Toronto
  • Arrival Timezone: Asia/Kolkata
  • Current Time in Toronto: Thursday 2026-04-09 06:19 AM
  • Current Time in Delhi: Thursday 2026-04-09 15:49 PM

Flight routes similar to Air Canada AC48

Airline Flight no Departure Arrival
Air India AI190
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Air Canada AC42
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United Airlines UA8160
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United Airlines UA6613
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Air Canada AC2348
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Air India AI3344
Air India 		09/04/2026
19:00 		0 minutes
05:30

Air Canada Flight AC48 FAQs

What is the scheduled flight duration for Air Canada AC48 flight?

On average, nonstop flight takes 15 hour(s) 20 minutes, with the flight distance of 11662 km (7246 miles).

What type of aircraft is used for the Air Canada AC48 flight?

All Air Canada AC48 flights are operated using Boeing 777-200LR aircraft.

Which terminal the flight Air Canada AC48 is arriving at?

Flight Air Canada AC48 arrives in Indira Gandhi International Airport at Terminal T3.